According to Archimedes' Principle, what is the buoyant force on a submerged object equal to?

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Multiple Choice

According to Archimedes' Principle, what is the buoyant force on a submerged object equal to?

Explanation:
Archimedes' Principle says the buoyant force on a submerged object equals the weight of the fluid the object displaces. In formula form, that’s F_b = ρ_fluid × V_displaced × g, where ρ_fluid is the fluid density, V_displaced is the submerged volume, and g is gravity. This shows buoyancy arises from pushing aside fluid: the more fluid you displace (larger submerged volume) or the denser the fluid, the greater the buoyant force. That’s why the statement in question is correct: the upward force matches the weight of the displaced fluid, not the object's weight or some unrelated quantity. The object’s weight is a downward gravitational force, not the buoyant force. A simple mass divided by depth isn’t a relevant measure for buoyancy, and while the fluid density is part of the calculation, density alone doesn’t determine the force without considering the displaced volume and gravity.

Archimedes' Principle says the buoyant force on a submerged object equals the weight of the fluid the object displaces. In formula form, that’s F_b = ρ_fluid × V_displaced × g, where ρ_fluid is the fluid density, V_displaced is the submerged volume, and g is gravity. This shows buoyancy arises from pushing aside fluid: the more fluid you displace (larger submerged volume) or the denser the fluid, the greater the buoyant force.

That’s why the statement in question is correct: the upward force matches the weight of the displaced fluid, not the object's weight or some unrelated quantity. The object’s weight is a downward gravitational force, not the buoyant force. A simple mass divided by depth isn’t a relevant measure for buoyancy, and while the fluid density is part of the calculation, density alone doesn’t determine the force without considering the displaced volume and gravity.

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